C++
[C++] 재귀호출로 회문 판별하기
렌더
2020. 8. 5. 23:16
#include<iostream>
#include<algorithm>
#include<string>
using namespace std;
int palindrome(string arr,int start,int end) {
if (start >= end)
return 0;
else if (arr[start] == arr[end])
return palindrome(arr, start + 1, end - 1);
else
return 1;
}
int main() {
string arr;
arr = "level";
int res;
res = palindrome(arr, 0, arr.size() - 1);
cout << res;
}